If the constellation cancer had a right ascencion of 8 hours how many degress would it be from the celestial?

equator! plees answer quick!If the constellation cancer had a right ascencion of 8 hours how many degress would it be from the celestial?Hi David!



Cancer stretches from 8 degrees north of the celestial equator to 35 degrees north.



Most of its stars are dim. The southernmost easily visible star, Beta Cancri, stands 9 degrees north, while Iota Cancri is 29 Degrees North.



Cancer's best known feature, Praesepe (the M44 nebula) lies near the mid-point of the constellation, at 20 North.